2b-6+(2b(b-6)^1/2)=9

Solution for 2b-6+(2b(b-6)^1/2)=9 equation:

2b-6+(2b(b-6)^1/2)=9

We move all terms to the left:

2b-6+(2b(b-6)^1/2)-(9)=0

We add all the numbers together, and all the variables

2b+(2b(b-6)^1/2)-15=0

We multiply all the terms by the denominator


2b*2)+(2b(b-6)^1-15*2)=0

We add all the numbers together, and all the variables

2b*2)+(2b(b-6)^1=0

Wy multiply elements

4b^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{8}=0$